MHT-CET PHYSICS - Target Publications
MHT-CETTRIUMPHPHYSICSHINTS TO MULTIPLE CHOICE QUESTIONS,EVALUATION TESTS&MHT-CET 2019 (6th May, Afternoon) PAPER
CONTENTSr. No.TextbookChapterNo.Chapter NamePage No.Std. XI11Measurements122Scalars and Vectors1234Force2645Friction in Solids and Liquids5158Refraction of Light6869Ray Optics84712Magnetic Effect of Electric Current99813Magnetism113Std. XII91Circular Motion121102Gravitation142113Rotational ace Tension232157Wave Motion244168Stationary Waves260179Kinetic Theory of Gases and Radiation2801810Wave Theory of Light3091911Interference and Diffraction3182012Electrostatics3372113Current Electricity3662214Magnetic Effect of Electric Current3852315Magnetism4042416Electromagnetic Induction4102517Electron hus and Photons4342618Atoms, Molecules and Nuclei4452719Semiconductors4702820Communicatio
T-CET Triumph Physics (Hints)24.From F at bt21 2 M1LT Fa [M1L1T 3] T1 t M1L1T 2 F [M1L1T 4]b 2 2 Tt 25. 26. 27. 28.2 M1L1/ 2 T 2 a 1 1 4 [L 1/2 T2]b M L T [M1L1T 2] [L2]a [L1T 1]b [M1L 3]c [L2a] [LbT b] [McL 3c] [Mc L2a b 3c T b]Comparing powers of M, L and T,c 1, 2a b 3c 1, b 2b 22a 2 3(1) 12a 2a 14π 2 a xLet T2 y zG M4 2 being pure number is dimensionless.[M 0 L1T 0 ]x[M0L0T2] [M-1L3T-2 ] y [M1L0 T 0 ]z [M0L0T2] [Lx] [M 1L3T 2] y [M1] zComparing powers of M, L and Ty z 0,x 3y 0 and 2y 2y 1Substituting value of y,z 1, x 34π 2 a 3Thus, T2 GMT PaDbSc[M0L0T1] [M1L 1T 2]a [M1L 3T0]b [M1L0T 2]cComparing powers of M, L, Ta b c 0, a 3b 0 and 2a 2c 131and c 1.Solving, a - , b 22In the given wave equation x denotesæ xödisplacement. Thus ççç has dimensions of T.è vøHence from the principle of homogenity k hasdimensions of T.30.F a x M1L1T 2 Fa [M1L1/2T 2] L1/ 2 xbt2 F M1L1T 2 F [M1L1T 4]b 2 t T 2 29. a t2bxa [t2] [T2]T2P bxP T T2b Px M1L 1T 2 L1 2 T 4 M1 M1 a2 [T ] 4 [M1T 2]b T 31. By principle of dimensional homogeneity a V 2 [P] [a] [P] [V2] [M1L 1T 2] [L6] [M1L5T 2]Dimensions of b are
ame as that of V,[b] [L3] M1L5T 2 a M1L2T 2 3 b L 32.Let G cxgypzSubstituting dimensions,[M 1L3T 2] [M0L1T 1]x [M0L1T 2]y [M1L 1T 2]zComparing powers of M, L, T 1 z,x y z 3 and x 2y 2z 2Solving, x 0, y 233.Acceleration due to gravity g g [L1T 2]a 1, b 21st systemL1 1 cm 10 5 km1T1 1 s min60abst22nd systemL2 1 kmT2 1 min1 10 5 km 1 /60 min n L 1 T 1 980 L2 T 2 1 km 1 min 980 10 5 3600 35.28 km min 2 2
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